Odd Polyhedral Cluster

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Odd Polyhedral Cluster

I stumbled upon this while using Stella 4d to modify existing polyhedra. You may find this program at http://www.software3d.com/Stella.php.

Octagonal Mandala II

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Octagonal Mandala

If the colors are inverted, but the background remains black, this is what it turns into:

radial octagonal mandala ic

Camping In Hexagonal Tents On a Tessellated Plane

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Camping In Hexagonal Tents On a Tessellated Plane

A Gallery of Nine Tessellations Using Hexagons

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hextess

Pictured above is the most familiar hexagonal tessellation. I’ve found some additional tessellations which use equilateral (but non-equiangular) hexagons, and have radial symmetry. They appear, using various coloring-schemes, below.

Hex radial tessellationHex radial tessellation 2Hex radial tessellation 3Hex radial tessellation 4radial octagonal mandala 2radial octagonal mandala 2Buntitleduntitled ic

A Rhombic Dodecahedron Featuring Rotating Pentagonal Mandalas

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A Rhombic Dodecahedron Featuring Rotating Pentagonal Mandalas

Geometer’s Sketchpad and MS-Paint were both used to make the images on the faces of this polyhedron, and then Stella 4d was used to put it all together and create this rotating image. Stella may be bought, and/or tried for free, at www.software3d.com/Stella.php.

Thirty Flying Rhombi

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Sixty Flying Rhombi

I used Stella 4d to make this image, and you can find that program at http://www.software3d.com/Stella.php.

Thirty Flying Hexagons

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Sixty Flying Hexagons

When I tweet a link to this blog-post as @robertlovespi, it will likely be quickly retweeted by @hexagonbot, simply because of the term “hexagon” being included in the tweet. What I don’t understand: Why do other polygons not have bots of their own?

I used Stella 4d to make this image, and you can find that program at http://www.software3d.com/Stella.php.

More Starry Polyhedra

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More Starry Polyhedra

These were all derived in various ways from the polyhedra seen in the last two posts. The rest are smaller at first, but each can be enlarged with a single click of your mouse. Each of them has icosidodecahedral symmetry.

Augmented Convex hullstellated Convex hullstellated Convex hull 2Astellated Convex hull 3stellation of mod of Compound of enantiomorphic pairstellation of mod of Compound of enantiomorphic pair 2stellation of mod of Compound of enantiomorphic pair 3

I used Stella 4d to make these images, and you can find that program at http://www.software3d.com/Stella.php.

The Archimedean Solid That Isn’t

A common definition for “Archimedean solid” goes like this:  Archimedean solids (1) are convex polyhedra, (2) include only faces which are regular, convex, non-intersecting polygons, (3) have more than one type of regular polygon used as faces, and (4) have the same set of polygons meeting at each vertex, in the same pattern. Archimedes himself enumerated the thirteen Archimedean solids, noted that two of them have mirror-images, and it has been proven that no more exist . . . provided the definition above is tweaked, just a little. Why isn’t this definition adequate? Here’s why.

ImageImage

By the definition given above, both of these polyhedra qualify as Archimedean solids . . . but only the top one is included in the official set of thirteen. It’s called the rhombcuboctahedron (or the rhombicuboctahedron). Both polyhedra shown have eighteen square faces, and eight triangular faces, all regular. In each one, also, the face-pattern around each vertex is square/square/square/triangle. However, the bottom figure, despite this, is not considered an Archimedean solid. Its existence is the reason — the only reason, to my knowledge — that the definition given above for the Archimedean solids is inadequate.

When I first encountered these two polyhedra side-by-side, I was reading Peter Cromwell’s excellent book, Polyhedra, and it showed them as simple black-and-white wire-frame images. It took an embarrassing amount of time for me to spot the difference between them, so please don’t feel bad if you also are having trouble seeing it. To spot the difference, if you haven’t already, watch the triangles. In the top image, which is a true Archimedean solid, the four triangles at the top of the polyhedron stay right above the corresponding four triangles at the bottom of the same polyhedron. In the second image, however, this is not the case, due to a 45° rotation of the bottom “cap” of the polyhedron shown.

To fix this problem, and exclude the second figure, an extra requirement has been added to the list that defines the Archimedean solids:  not only must each vertex be locally identical, but there must also be a global isometry shared by all vertices. In lay terms, that means that you can look at any vertex you choose, and see the same pattern for the other vertices, their orientation relative to each other, and the orientation of the faces surrounding them, as well. The first polyhedron shown here passes this test, but the second does not.

This troublesome-but-interesting second polyhedron has several names. I usually call it the pseudorhombcuboctahedron. Other names include the pseudorhombicuboctahedron (note the extra “i”), and Miller’s solid (based on the work of J.C.P. Miller, as described in Cromwell’s book). As #37 in Norman Johnson’s set of 92 Johnson solids, of which it is unambiguously a member, it is called the elongated square gyrobicupola. Finally, there are people who disagree with what I have written above . . . and they often refer to the bottom polyhedron shown as, simply, “the fourteenth Archimedean solid.”

Image credit:  both pictures above were generated using Stella 4d, software you can buy, or try for free, at www.software3d.com/Stella.php.

A Half-Solved Mystery: Rotating a Sine Wave

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A Half-Solved Mystery

A few minutes ago, I wondered how to write a function whose graph would be a sine curve, but one that undulated above and below the diagonal line y=x, rather than the x-axis, as is usually the case. How to accomplish such a 45 degree counterclockwise rotation?

Well, first, I abandoned degrees, set Geometer’s Sketchpad to radians, and then simply constructed plots for both y = x and y = sin(x). Next, I added them together. The result is the green curve (and equation) you see above.

This only half-solves the problem. Does it undulate above and below y=x? Yes, it does. However, if you rotate this whole thing, clockwise, one-eighth of a complete turn, so that you are looking at the green curve going along the x-axis, you’ll notice that it is not a true sine curve, but a distorted one. Why? Because it was generated by adding y-values along the original x-axis, not by a true rotation.

I’m not certain how to correct for this distortion, or otherwise solve the problem. If anyone has a suggestion, please leave it in a comment. [Note: an astute follower of this blog has now done exactly that, so I refer the reader to the comments for the rest of the story here.]